x^2-2x-0.25=0

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Solution for x^2-2x-0.25=0 equation: 



x^2-2x-0.25=0

a = 1; b = -2; c = -0.25;
Δ = b2-4ac
Δ = -22-4·1·(-0.25)
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{5}}{2*1}=\frac{2-\sqrt{5}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{5}}{2*1}=\frac{2+\sqrt{5}}{2}
$

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